The Odds of Four People Submitting Identical Brackets Through the Sweet 16

The NCAA’s official schedule shows that the first three rounds are the First Round, Second Round, and Sweet 16. Quote: “First round: Thursday, March 19 and Friday, March 20 … Second round: Saturday, March 21 and Sunday, March 22 … Sweet 16: Thursday, March 26 and Friday, March 27.”

With 266 entries, the number of possible 4-person groups is(2664)=203,927,570\binom{266}{4}=203{,}927{,}570

For a specific group of 4 brackets to all match on one game under this chalk model, the probability isq4+(1q)4q^4+(1-q)^4

because either all 4 take the favorite, or all 4 take the other side. Across 56 games total, the probability that a specific group of 4 matches exactly through the first three rounds is(q4+(1q)4)56.\left(q^4+(1-q)^4\right)^{56}.

So for any 4 out of 266 entries, the rare-event approximation is(2664)(q4+(1q)4)56\boxed{ \binom{266}{4}\left(q^4+(1-q)^4\right)^{56} }

That is the revised “chalk bias” formula.

Here are a few illustrative versions.

If entrants pick the favorite 70% of the time, then:(2664)(0.74+0.34)562.62×1026\binom{266}{4}\left(0.7^4+0.3^4\right)^{56}\approx 2.62\times 10^{-26}

which is about 1 in 38,161,420,710,655,820,000,000,000.

If entrants pick the favorite 75% of the time, then:(2664)(0.754+0.254)564.18×1020\binom{266}{4}\left(0.75^4+0.25^4\right)^{56}\approx 4.18\times 10^{-20}

which is about 1 in 23,899,365,976,853,120,000.

If entrants pick the favorite 80% of the time, then:(2664)(0.84+0.24)564.97×1014\binom{266}{4}\left(0.8^4+0.2^4\right)^{56}\approx 4.97\times 10^{-14}

which is about 1 in 20,116,393,414,950.

A more realistic version is to let chalkiness vary by round. For example:

  • First round favorite rate q1=0.75q_1=0.75q1​=0.75 across 32 games
  • Second round favorite rate q2=0.70q_2=0.70q2​=0.70 across 16 games
  • Sweet 16 favorite rate q3=0.65q_3=0.65q3​=0.65 across 8 games

Then the formula becomes(2664)(q14+(1q1)4)32(q24+(1q2)4)16(q34+(1q3)4)8\boxed{ \binom{266}{4} \left(q_1^4+(1-q_1)^4\right)^{32} \left(q_2^4+(1-q_2)^4\right)^{16} \left(q_3^4+(1-q_3)^4\right)^{8} }(4266​)(q14​+(1−q1​)4)32(q24​+(1−q2​)4)16(q34​+(1−q3​)4)8​

Plugging those values in gives about1.25×10231.25\times 10^{-23}1.25×10−23

or roughly 1 in 79,736,844,641,242,890,000,000.

So the bottom line is: once you add chalk bias, the odds become vastly higher than the pure-random model, but they are still extremely small unless the pool is very chalk-heavy, brackets are copied, or many entrants are using near-identical heuristics.

Quote used for the round structure: “First round … Second round … Sweet 16.”

I can also turn this into a one-line explainer you could quote in a story, with a conservative, moderate, and aggressive chalk scenario.